问题补充:
∠DCE=90°CD=CE AD⊥CE AD⊥AC BE⊥AC 垂足分别为A B 试说明AD+AB=BE
答案:
∵AD⊥AC,BE⊥AC ∴∠DAC=∠CBE=90°∵∠DCA ∠ECA=90° ∠DCA ∠D=90°∴∠ECA=∠D在△ADC和△BCE中{∠DAC=∠CBE ∠ECA=∠D DC=EC
时间:2019-08-27 13:20:08
∠DCE=90°CD=CE AD⊥CE AD⊥AC BE⊥AC 垂足分别为A B 试说明AD+AB=BE
∵AD⊥AC,BE⊥AC ∴∠DAC=∠CBE=90°∵∠DCA ∠ECA=90° ∠DCA ∠D=90°∴∠ECA=∠D在△ADC和△BCE中{∠DAC=∠CBE ∠ECA=∠D DC=EC