问题补充:
在(x-y+z)(x+y-z)=[x+( )][x-( )]的括号内应填上的代数式是A.z-y,z-yB.z-y,z+yC.y+z,y+zD.y+z,y-z
答案:
A解析(x-y+z)(x+y-z)=(x+z-y)(x-z+y)=[x+(z-y)][x-(z-y)]∴正确
时间:2021-11-06 06:10:32
在(x-y+z)(x+y-z)=[x+( )][x-( )]的括号内应填上的代数式是A.z-y,z-yB.z-y,z+yC.y+z,y+zD.y+z,y-z
A解析(x-y+z)(x+y-z)=(x+z-y)(x-z+y)=[x+(z-y)][x-(z-y)]∴正确
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2024-07-01