问题补充:
已知实数X、Y、Z满足│X-Y+2│+√2x-3y-2+z^2 -4z+4=0,求4x-3√y+√z^2的值.
答案:
│X-Y+2│+√2x-3y-2+z^2 -4z+4
=│X-Y+2│+√2x-3y-2+(z-2)^2
=0x-y+2=0
2x-3y-2=0
z=2解方程组得:
x=-8,y=-6,z=2
4x-3√y+√z^2没有意义
---------------题目错了
======以下答案可供参考======
供参考答案1:
│X-Y+2│+√2x-3y-2+z^2 -4z+4
=│X-Y+2│+√2x-3y-2+(z-2)^2
=0 x-y+2=0
2x-3y-2=0
z=2 解方程组得:
x=-8,y=-6,z=2
4x-3√y+√z^2没有意义