问题补充:
已知,在RT三角形ABC中,∠ACB=90'AC =6,BC=8过直角顶点C做CA1⊥AB垂足为A已知,在RT三角形ABC中,∠ACB=90'AC=6,BC=8过直角顶点C做CA1⊥AB垂足为A1,再过A1做A1C1⊥BC垂足为C1过C1做C1A2⊥AB……一直做下去得到一组线段,CA1,A1C1,C1A2,A2C2则AnCn=
答案:
6*(8/10)^(2n)
时间:2022-08-23 17:23:48
已知,在RT三角形ABC中,∠ACB=90'AC =6,BC=8过直角顶点C做CA1⊥AB垂足为A已知,在RT三角形ABC中,∠ACB=90'AC=6,BC=8过直角顶点C做CA1⊥AB垂足为A1,再过A1做A1C1⊥BC垂足为C1过C1做C1A2⊥AB……一直做下去得到一组线段,CA1,A1C1,C1A2,A2C2则AnCn=
6*(8/10)^(2n)