F(x2+yz y2+xz)=0确定函数z=z(x y)求dz补充图片

问题补充：

F(x2+yz,y2+xz)=0确定函数z=z(x,y)求dz补充图片

答案：

dz=-Fx/Fz *dx -Fy/Fz *dy

Fx=F1*2x+F2*z

Fy=F1*z+F2*2y

Fz=F1*y+F2*x

dz=-Fx/Fz *dx -Fy/Fz *dy

=-(F1*2x+F2*z)/(F1*y+F2*x)dx-(F1*z+F2*2y)/(F1*y+F2*x)dy

解毕