问题补充:
77已知△ABC,作等腰△ABD与等腰△ACE,使AB=AD,AC=AE,∠BAD=∠CAE,直线CD、BE交于O.3)如图③:若∠BAD=∠CAE=α,α为钝角,则∠BOD与α的数量关系是 ;
答案:
设AC与BE交于F∵∠BAD=∠CAE∴∠BAD+∠BAC=∠CAE+∠BAC即∠BAE=∠CAD∵AB=AD,AC=AE∴△ABE≌△ACD∴∠AEB=∠ACD即∠AEF=∠FCO∵∠AFE=∠OFC(对顶角)∴△AEF∽△FCO∴∠FOC=∠FAE=∠CAE=α∵∠BOD=∠FOC(对顶角)∴∠...
======以下答案可供参考======
供参考答案1:
图呢?