问题补充:
已知实数abc满足a=6-b,c^2=ab-9,求abc
答案:
c^2=ab-9=(6-b)*b-9>=0b^2-6b+9(b-3)^2因为(b-3)^2>=0so(b-3)^2=0
sob=3a=6-3=3
c=0 所以a=3b=3c=0abc=0
时间:2024-06-28 13:14:38
已知实数abc满足a=6-b,c^2=ab-9,求abc
c^2=ab-9=(6-b)*b-9>=0b^2-6b+9(b-3)^2因为(b-3)^2>=0so(b-3)^2=0
sob=3a=6-3=3
c=0 所以a=3b=3c=0abc=0